Question
The _______ distance between TVC and TC is ________.
- Vertical, TFC.
- Horizontal, TFC.
- Horizontal, AFC.
- Vertical, AFC.
✓
Answer
- Vertical, TFC.
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$\text{APS}=\frac{\Delta\text{C}}{\Delta\text{Y}}$
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$\text{APS}=\frac{\text{Y}}{\text{S}}$
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$\text{APS}=\frac{\text{S}}{\text{Y}}$
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