The distance covered by a particle undergoing $SHM$ in one time period is (amplitude $= A$)
NEET 2019, Easy
Download our app for free and get started
Distance in one oscillation $= 4A$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The time period of a simple pendulum is $2\, sec$. If its length is increased $4$ times, then its period becomes ..... $\sec$View Solution
- 2The velocity-time diagram of a harmonic oscillator is shown in the adjoining figure. The frequency of oscillation is ..... $Hz$View Solution
- 3View SolutionResonance is an example of
- 4Figure shows the position-time graph of an object in $S.H.M.$ The correct equation representing this motion is ..........View Solution
- 5The total energy of particle performing $S.H.M.$ depend onView Solution
- 6Two equations of two $S.H.M.$ are $y = a\sin \,(\omega \,t - \alpha )$ and $y = b\cos (\omega \,t - \alpha )$. The phase difference between the two is .... $^o$View Solution
- 7View SolutionWhich of the following expressions represent simple harmonic motion
- 8A damped harmonic oscillator has a frequency of $5$ oscillations per second. The amplitude drops to half its value for every $10$ oscillations. The time it will take to drop to $\frac{1}{1000}$ of the original amplitude is close to .... $s$View Solution
- 9A particle moving along the $X-$axis executes simple harmonic motion, then the force acting on it is given byView Solution
Where $A$ and $K$ are positive constants
- 10The displacement of a particle moving in $S.H.M.$ at any instant is given by $y = a\sin \omega t$. The acceleration after time $t = \frac{T}{4}$ is (where $T$ is the time period)View Solution