MCQ
The domain of function $f(x)=\frac{1}{\sqrt{|x|-x}}$ is :
- A$R ^{+}$
- ✓$R ^{-}$
- C$R _0$
- D$R$
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Then $\left(\frac{\mathrm{AM} \cdot \mathrm{BN}}{\mathrm{CD}}\right)^2$ is equal to...........
$f(x)=\frac{1}{2+\sin 3 x+\cos 3 x}, x \in \operatorname{IR} \text { be }[a, b] .$ If $\alpha$ and $\beta$ are respectively the $A.M.$ and the $G.M.$ of a and $b$, then $\frac{\alpha}{\beta}$ is equal to :