MCQ
The domain of $f(x) = \frac{{{{\log }_2}(x + 3)}}{{{x^2} + 3x + 2}}$ is
  • A
    $R - \{ - 1,\; - 2\} $
  • B
    $( - 2,\; + \infty )$
  • C
    $R - \{ - 1,\; - 2,\; - 3\} $
  • $( - 3,\; + \infty ) - \{ - 1,\; - 2\} $

Answer

Correct option: D.
$( - 3,\; + \infty ) - \{ - 1,\; - 2\} $
d
(d) Here $x + 3 > 0$ and ${x^2} + 3x + 2 \ne 0$

$\therefore$ $x > - 3$ and $(x + 1)(x + 2) \ne 0,$  $i.e.$  $x \ne - 1,\, - 2$

$\therefore$ Domain$ = ( - 3,\,\infty ) - \{ - 1,\, - 2\} $.

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