MCQ
The domain of the function $f(x) = \frac{{{{\sin }^{ - 1}}(x - 3)}}{{\sqrt {9 - {x^2}} }}$ is
- A$[1, 2)$
- ✓$[2, 3)$
- C$[1, 2]$
- D$[2, 3]$
$9 - {x^2} > 3 \Rightarrow - 3 < x < 3.....(i)$
$ - 1 \le (x - 3) \le 1 \Rightarrow 2 \le x \le 4.....(ii)$
From $(i)$ and $(ii)$, $2 \le x < 3$ $i.e.,\,\, [2, 3).$
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$A=\left\{(x, y):|\cos x-\sin x| \leq y \leq \sin x, 0 \leq x \leq \frac{\pi}{2}\right\}$