MCQ
The domain of the function $f(x) = {\sin ^{ - 1}}[{\log _2}(x/2)]$ is
- ✓$[1, 4]$
- B$[-4, 1]$
- C$[-1, 4]$
- DNone of these
==> $ - 1 \le {\log _2}(x/2) \le 1$ ==> $\frac{1}{2} \le \frac{x}{2} \le 2$
==> $1 \le x \le 4$
$\therefore$ $x \in [1,\,4]$.
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