MCQ
The domain of the function $f(x)=\sqrt{x-1}+\sqrt{6-x}$
  • A
    $(-\infty, 6)$
  • B
    $[2,6]$
  • C
    $[1,6]$
  • D
    $[-2,6]$

Answer

(c) $[1,6]$
Explanation: For $f(x)$ to be real, we must have,
$\begin{array}{l}x-1 \geqslant 0 \text { and } 6-x \geqslant 0 \\ \Rightarrow x \geqslant \varphi \text { and } x-6 \leqslant 6 \\ \therefore \text { Domain }=[1,6]\end{array}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free