MCQ
The domain of the function $y = \frac{1}{{\sqrt {|x|\; - x} }}$ is
- ✓$( - \infty ,\;0)$
- B$( - \infty ,\;0]$
- C$( - \infty ,\; - 1)$
- D$( - \infty ,\;\infty )$
$|x|\,\, > x$ but $|x|\,\, = x$ for $x $ positive and $|x|\,\, > x$ for $ x $ negative.
So, domain will be $( - \,\infty ,\,\,0)$.
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($A$) differentiable at $x=0$ if $a=0$ and $b=1$
($B$) differentiable at $x=1$ if $a=1$ and $b=0$
($C$) $NOT$ differentiable at $x=0$ if $a=1$ and $b=0$
($D$) $NOT$ differentiable at $x=1$ if $a=1$ and $b=1$