- A1
- B0
- C$\frac{5}{16}$
- ✓$\frac{5}{4}$
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Equations of diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1 are:
-2
0
$\frac{1}{2}$
does not exist
Choose the correct answer.
If the middle term of $\Big(\frac{1}{\text{x}}+\text{x}\sin\text{x}\Big)^{10}$ is equal to $7\frac{7}{8},$ then value of x is:
$2\text{n}\pi+\frac{\pi}{6}.$
$\text{n}\pi+\frac{\pi}{6}.$
$\text{n}\pi+(-1)^\text{n}\frac{\pi}{6}.$
$\text{n}\pi+(-1)^\text{n}\frac{\pi}{3}.$
Hint: $\text{T}_6=\ ^{10}\text{C}_5\frac{1}{\text{x}^5}.\text{x}^5\ \sin^5\text{x}=\frac{63}{8}\Rightarrow\sin^5\text{x}=\frac{1}{2^5}\sin\frac{1}{2}$
$\Rightarrow\text{x}=\text{n}\pi+(-1)^\text{n}\frac{\pi}{6}$