$E=200\left[\sin \left(6 \times 10^{15}\right) t+\sin \left(9 \times 10^{15}\right) t\right] \,Vm ^{-1}$
Given : $h=4.14 \times 10^{-15} \,eVs$
If this light falls on a metal surface having a work function of $2.50 \,eV$, the maximum kinetic energy of the photoelectrons will be ........... $eV$
- A$1.90$
- B$3.27$
- C$3.60$
- ✓$3.42$