The electric potential at any point as a function of distance $(x)$ in meter is given by  $V = 5x^2 + 10x -9 \,(volt)$ Value of electric field at $x = 1$ is......$Vm^{-1}$
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$ \mathrm{E} =-\frac{\mathrm{dV}}{\mathrm{dx}}=-(10 \mathrm{x}+10)=-(10+10) $

$=-20 \mathrm{\,Vm}^{-1}$

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