MCQ
The electron affinities of halogens are $F = 322$, $Cl = 349$, $Br = 324$, $I = 295\,kJ\,mo{l^{ - 1}}$. The higher value for $Cl$ as compared to that of $F$ is due to
  • Weaker electron-electron repulsion in $Cl$
  • B
    Higher atomic radius of $F$
  • C
    Smaller electronegativity of $F$
  • D
    More vacant $P$ - subshell in $Cl$

Answer

Correct option: A.
Weaker electron-electron repulsion in $Cl$
a
Electron affinity value of $Cl$ is higher than of $F$ as $Cl$ belongs to the $3^{rd}$ period while $F$ belongs to $2^{nd}$ period. In $Cl$, electron-electron repulsion forces are weaker than that of $F$.

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