MCQ
The electron is
- A$\alpha $-ray particle
- ✓$\beta $-ray particle
- CHydrogen ion
- DPositron
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$1.$ The metal rod ${M}$ is
$(A)$ $\mathrm{Fe}$ $(B)$ $\mathrm{Cu}$ $(C)$ $\mathrm{Ni}$ $(D)$ $\mathrm{Co}$
$2.$ The compound ${N}$ is
$(A)$ $\mathrm{AgNO}_3$ $(B)$ $\mathrm{Zn}\left(\mathrm{NO}_3\right)_2$
$(C)$ $\mathrm{Al}\left(\mathrm{NO}_3\right)_3$ $(D)$ $\mathrm{Pb}\left(\mathrm{NO}_3\right)_2$
$3.$ The final solution contains
$(A)$ $\left[\mathrm{Pb}\left(\mathrm{NH}_3\right)_4\right]^{2+}$ and $\left[\mathrm{CoCl}_4\right]^{2-}$
$(B)$ $\left[\mathrm{Al}\left(\mathrm{NH}_3\right)_4\right]^{3+}$ and $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$
$(C)$ $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$and $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$
$(D)$ $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$and $\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}$
Give the answer question $1,2$ and $3.$