MCQ
The electronegativity of the following elements increases in the order
- A$C < N < Si < P$
- ✓$Si < P < C < N$
- C$N < C < P < Si$
- D$C < Si < N < P$
In a period, electronegativity increases from left to right.
In a group, the electronegativity decreases down the group.
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Given : $N -N =159\,kJ\,mol^{-1};\,\,H-H = 436\,kJ\,mol^{-1}$
$N \equiv N = {\text{ }}941{\text{ }}kJ{\text{ }}mo{l^{ - 1}}{\text{ }};{\text{ }}N-H{\text{ }} = {\text{ }}398{\text{ }}kJ{\text{ }}mo{l^{ - 1}}$ .....$kJ\,mol^{-1}$
$CH_3CH_2OH$ $\xrightarrow{{P + {I_2}}}A\xrightarrow[{{\text{dry ether}}}]{{Mg}}B\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D$ the compound $D$ is

$H _2 O (\ell) \rightarrow H _2 O ( g )$
at $T =100^{\circ} C$ and $1$ atmosphere pressure, the correct choice is :