MCQ
The electronic configuration of $Ag$ atom is
- A$\left[ {Kr} \right]3{d^{10}}4{s^1}$
- B$\left[ {Xe} \right]4{f^{14}}{d^{10}}6{s^1}$
- ✓$\left[ {Kr} \right]4{d^{10}}5{s^1}$
- D$\left[ {Kr} \right]4{d^9}5{s^2}$
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Reason : The third ionization energy of $Mn$ is larger than that of $Cr$.
