MCQ
The electronic configuration of cobalt is
- A$1{s^2},2{s^2}2{p^6}.3{s^2}3{p^6}3{d^1},4{s^2}$
- ✓$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^7},4{s^2}$
- C$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^3},4{s^2}$
- D$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^5},4{s^2}$
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$\begin{array}{*{20}{c}}
{{C_2}{H_5}MgBr + {H_2}C - C{H_2}\xrightarrow{{{H_2}O}}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\backslash \,\,\,\,/} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}A$
$Fe|F{e^{ + 2}}\left( {0.2\,M} \right)||A{u^{ + 3}}\left( {0.02\,M} \right)|Au$, If $E_{F{e^{ + 2}}/Fe}^o = - 0.44\,V$ and $E_{Au/A{u^{ + 3}}}^o = - 1.50\,V$