MCQ
The electronic configuration of element with atomic no. $14$ is :
- A$(2, 6, 6)$
- B$(4, 6, 4)$
- C$(2, 4, 8)$
- ✓$(2, 8, 4)$
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$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$
The state of hybridization of carbons $1, 3$ and $5$ are in the following sequence