MCQ
The electronic configuration of four elements $L, P, Q$ and $R$ are given in brackets $L\,\left( {1{s^2},\,\,2{s^2}\,2{p^4}} \right);\,\,Q\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}\,\,3{p^5}} \right)$;$P$

$\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^1}} \right);\,\,R\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}} \right)$The formula of ionic compounds that can be formed between these elements are

  • A
    ${L_2}P,\,\,RL,\,\,PQ$ and ${R_2}Q$
  • B
    $LP,\,\,RL,\,\,PQ$ and $RQ$
  • ${P_2}L,\,\,RL,\,\,PQ$ and $R{Q_2}$
  • D
    $LP,\,\,{R_2}L,\,\,{P_2}Q$ and $RQ$

Answer

Correct option: C.
${P_2}L,\,\,RL,\,\,PQ$ and $R{Q_2}$
(c) Valencies of $L$, $Q$, $P$ and $R$ is $-2$, $-1$, $+ 1$ and $+ 2$ respectively so they will form ${P_2}L,\,\,RL,$ $PQ$ and $R{Q_2}$.

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