MCQ
The electronic configuration of four elements $L, P, Q$ and $R$ are given the brackets

$L(1s^2, 2s^2 2p^4); Q(1s^2, 2s^2 2p^6, 3s^2 3p^5)$
$P(1s^2, 2s^2 2p^6, 3s^1); R(1s^2, 2s^2 2p^6, 3s^2)$

The formulae of ionic compounds that can be formed between these elements are

  • A
    $L_2P, RL, PQ$ and $R_2Q$
  • B
    $LP, RL, PQ$ and $RQ$
  • $P_2L, RL, PQ$ and $RQ_2$
  • D
    $LP, R_2L, P_2Q$ and $RQ$

Answer

Correct option: C.
$P_2L, RL, PQ$ and $RQ_2$
c
Valencies of $L, Q, P$ and $R$ is $-2, -1, +1$ and $+2$ respectively so they will form $P_2L, RL, PQ$ and $RQ_2$.

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