MCQ
The electronic configuration of gadolinium (atomic no. $64$) is
- A$[Xe]4{f^8}5{d^9}6{s^2}$
- ✓$[Xe]4{f^7}5{d^1}6{s^2}$
- C$[Xe]4{f^3}5{d^5}6{s^2}$
- D$[Xe]4{f^6}5{d^2}6{s^2}$
✓
Answer
Correct option: B.
$[Xe]4{f^7}5{d^1}6{s^2}$
b
The electronic configuration of $L a\,(Z=57)$ is $[X e] \,5 d^1\, 6 s^2$
The electronic configuration of $L a\,(Z=57)$ is $[X e] \,5 d^1\, 6 s^2$
Therefore, further addition of electrons occurs in the lower energy $4 f$ - orbital till it is exactly half filled at $Eu \,(Z=63)$
Thus, the electronic configuration of $Eu$ is $[ Xe ] \,4 f ^7 \,6 s ^2$, thereafter, addition of next electron does not occur in the more stable exactly half filled $4 f^7$ shell but occurs in the little higher energy $5 d$ - orbital.
Thus, the electronic configuration of $Gd (Z=64)$ is $[X e]\, 4 f^7\, 5 d^1\, 6 s^2$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$K_2MnO_4$ can be converted into $KMnO_4$ by
→Which of the following will not produce $CH_4$ gas with $CH_3MgBr$ ?
→Maximum number of atoms which are present in one plane of $H_3BO_3$?
→The most stable ion is
In the sequence of the following reactions $C{{H}_{3}}C{{H}_{2}}OH$ $\underset{\text{ChromicAcid}}{\mathop{\xrightarrow{[\text{O }\!\!]\!\!\text{ }}}}\,X\underset{\text{ChromicAcid}}{\mathop{\xrightarrow{[O]}}}\,$ $C{{H}_{3}}COOH$
→$X$ is
Which carbocation is the most stabilized ?
Which of the following is in the increasing order of the ionic character
Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by the other ?
The order of reactivity of following compounds towards sodalime decarboxylation reaction ?
The expression for the solubility product of $A{l_2}\,{(S{O_4})_3}$ is
→