MCQ
The electronic configuration of Gadolinium is
- A$[Xe]6s^2\,\,4f^8$
- B$[Xe] 6s^2\,\, 5d^1\,\, 4f^8$
- ✓$[Xe] 6s^2\,\,5d^1\,\,4f ^7$
- DNone
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Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$
$C{H_2} = CH{(C{H_2})_8}COOH + HBr\xrightarrow{{{\text{peroxide}}}}$