MCQ
The electronic configuration (outermost) of $M{n^{ + 2}}$ ion (atomic number of $Mn = 25$) in its ground state is
  • $3{d^5},4{s^0}$
  • B
    $3{d^4},4{s^1}$
  • C
    $3{d^3},4{s^2}$
  • D
    $3{d^2},4{s^2}4{p^2}$

Answer

Correct option: A.
$3{d^5},4{s^0}$
a
$_{25}Mn = [Ar]\,3{d^5}4{s^2} - 2 e^-$ $\rightleftharpoons $ $M{n^{2 + }} = [Ar]\,\,3{d^5}\,4{s^0}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free