
- ✓dichlorocarbene $(: CCl_2)$
- Btrichloromethyl anion $(\mathop C\limits^\Theta Cl_3)$
- Cformyl cation $(\mathop C\limits^ \oplus HO)$
- Ddichloromethyl cation $(\mathop C\limits^ + HCl_2)$

In Reimer-Tiemann reaction, phenol in presence of $NaOH$ reacts with chloroform to give salicyladehyde.
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$\lambda_{\mathrm{m}\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{x} \;\mathrm{S}\; \mathrm{cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{y} \;\mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}(\mathrm{CH_3} \mathrm{COOK})}^{0}=\mathrm{z}\; \mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ for $\mathrm{CH}_{3} \mathrm{COOH}$ will be

${C_6}{H_5} - COO - C{H_3}\mathop {\xrightarrow{{1.\,LiAl{H_4}}}}\limits_{2.\,{H_2}O} $