The electrostatic potential inside a charged spherical ball is given by $\phi= a{r^2} + b$ where $r$ is the distance from the centre and $a, b$ are constants. Then the charge density inside the ball is:
  • A$-24\pi a{\varepsilon _0}r$
  • B$- 6$$a{\varepsilon _0}r$
  • C$-24$$\pi a{\varepsilon _0}$
  • D$- 6$$a{\varepsilon _0}$
AIEEE 2011, Diffcult
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