MCQ
The element having electronic configuration belongs to $n{s^2}(n - 1){d^{1 - 10}}(n - 2){f^{1 - 14}}$
- A$s-$ block
- B$p-$ block
- C$d-$ block
- ✓$f-$ block
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Reason : Fluorine has $2s^2\,2p^5$ configuration.
| Bromine | $Na$ metal | Chromic acid | Lucas reagent | |
| Compound $X$ | decolourises | bubbles | Orange to Green | No reaction |
| Compound $Y$ | No reaction | No reaction | No reaction | No reaction |
Compound $X$ and $Y$ respectively are
