MCQ
The $(e/m)$ for positive rays in comparison to cathode rays is
- ✓Very low
- BVery high
- CSame
- DNone
$\therefore e / m$ ratio for cathode rays is very low.
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$(A)$ $\Delta U = q + p \Delta V$
$(B)$ $\Delta G =\Delta H - T \Delta S$
$(C)$ $\Delta S =\frac{ q _{ rev }}{ T }$
$(D)$ $\Delta H =\Delta U -\Delta nRT$
Choose the most appropriate answer from the options given below :