MCQ
The emission spectrum of hydrogen is found to satisfy the expression for the energy change. $\Delta E$ (in joules) such that $\Delta E = 2.18 \times 10\left( {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right)\,\,J$ where ${n_1}$ $= 1, 2, 3$….. and ${n_2}$ $= 2, 3, 4…….$ The spectral lines correspond to Paschen series to
  • A
    ${n_1} = 1$ and ${n_2} = 2,\,\,3,\,\,4$
  • ${n_1} = 3$ and ${n_2} = 4,\,\,5,\,\,6$
  • C
    ${n_1} = 1$ and ${n_2} = 3,\,\,4,\,\,5$
  • D
    ${n_1} = 2$ and ${n_2} = 3,\,\,3,\,\,5$

Answer

Correct option: B.
${n_1} = 3$ and ${n_2} = 4,\,\,5,\,\,6$
b
In the emission spectra of hydrogen atom, Paschen series is the one where the transition from higher energy states to third energy state takes place.

i.e. $n_{ f }=n_1=3$ and $n_i=n_2\,>\,3$

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