The end correction of a resonance column is $1\,cm.$ If the shortest length resonating with the tuning fork is $10\,cm,$ the next resonating length should be ..... $cm$
JEE MAIN 2018, Medium
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For first resonance, $\frac{\lambda}{4}=\ell_{1}+\mathrm{e}=11 \mathrm{cm}$
$(\because \text { end correction } \mathrm{e}=1 \mathrm{cm} \text { given })$
For second resonance, $\frac{3 \lambda}{4}=\ell_{2}+\mathrm{e}$
$\Rightarrow \ell_{2}=3 \times 11-1=32 \mathrm{cm}$
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