The end product of the reaction {text{ethyl amine}}xrightarrow{{{text{HN}}{{text{O}}_{text{2}}}}}Axrightarrow{{PC{l

Q: The end product of the reaction ${\text{ethyl amine}}\xrightarrow{{{\text{HN}}{{\text{O}}_{\text{2}}}}}A\xrightarrow{{PC{l_5}}}B\xrightarrow{{KCN}}C$ is

c (c) ${C_2}{H_5}N{H_2} + HN{O_2} \to {C_2}\mathop {{H_5}O}\limits_{(A)} H + {N_2} + {H_2}O$ ${C_2}{H_5}OH + PC{l_5} \to \mathop {{C_2}{H_5}}\limits_{(B)} Cl + POC{l_3} + HCl$ ${C_2}{H_5}Cl + KCN \to \mathop {{C_2}{H_5}CN}\limits_{(C){\text{Propane nitrile}}} + KCl$

SECTION - A [CHEMISTY - MCQ]

GSEB - English Medium

The end product of the reaction ${\text{ethyl amine}}\xrightarrow{{{\text{HN}}{{\text{O}}_{\text{2}}}}}A\xrightarrow{{PC{l_5}}}B\xrightarrow{{KCN}}C$ is

A
Ethyl amine
B
Diethyl amine
C
Propane nitrile
D
Triethyl amine(e)Methyl amine

Medium

STD 11 Science
JEE
STD 12 - 9. Amines
Chemistry

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