The energy of an electron in the first Bohr’s orbit of H atom is … - Vidyadip

MCQ

The energy of an electron in the first Bohr’s orbit of $H$ atom is $-13.6\,eV.$ The possible energy value (s) of the excited state (s) for electron in Bohr’s orbits of hydrogen is (are) : ............. $\mathrm{eV}$

✓
$-3.4$
B
$-4.2$
C
$-6.8$
D
$+6.8$

✓

Answer

Correct option: A.

$-3.4$

a
As we know,

$E=-13.6 \times Z^{2} / n^{2}$

So, $E_{1}$ for $H=-13.6 \mathrm{eV}$

$E_{2}=\frac{-13.6}{4}=-3.4 \mathrm{eV}$

$E_{3}=\frac{-13.6}{9}=-1.51$

$E_{4}=\frac{-13.6}{16}=-0.85$ and so on.

Hence, the correct option is $A$

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