MCQ
The equation $2{\cos ^{ - 1}}x + {\sin ^{ - 1}}x = \frac{{11\pi }}{6}$ has
- ✓No solution
- BOnly one solution
- CTwo solutions
- DThree solutions
==> ${\cos ^{ - 1}}x + ({\cos ^{ - 1}}x + {\sin ^{ - 1}}x) = \frac{{11\pi }}{6}$
==> ${\cos ^{ - 1}}x + \frac{\pi }{2} = \frac{{11\pi }}{6}$
$ \Rightarrow {\cos ^{ - 1}}x = 4\pi /3$
which is not possible as ${\cos ^{ - 1}}x \in [0,\,\pi ]$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Statement $I:$ $f$ is a continuous function at $x = 0.$
Statement $II:$ $g$ is a differentiable function at $x = 0.$