MCQ
The equation ${\log _e}x + {\log _e}(1 + x) = 0$ can be written as
- A${x^2} + x - e = 0$
- ✓${x^2} + x - 1 = 0$
- C${x^2} + x + 1 = 0$
- D${x^2} + xe - e = 0$
$⇒$ $x(x + 1) = 1\,\, \Rightarrow \,\,{x^2} + x - 1 = 0$
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