The equation of the circle passing through (3, 6) and whose centr… - Vidyadip

MCQ

The equation of the circle passing through $(3, 6)$ and whose centre is $(2, -1)$ is:

✓
$ x^2+y^2-4 x+2 y=45 $
B
$ x^2+y^2-4 x-2 y+45=0 $
C
$ x^2+y^2+4 x-2 y=45 $
D
$ x^2+y^2-4 x+2 y+45=0 $

✓

Answer

Correct option: A.

$ x^2+y^2-4 x+2 y=45 $

Equation of circle, $(\text{x} - 2)^2 + (\text{y} -( -1))^2= \Big(\sqrt{{(3-2)^2+(6}-(-1))^2\Big)}^2$
$\text{x}^2 - 4\text{x} + 4 + \text{y}^2 + 2\text{y} + 1=(\sqrt{1+49})^2$
$\therefore\text{x}^2+\text{y}^2-4\text{x}+2\text{y}=45$ Equation of circle.

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