The equation of travelling wave is $y=a \sin 2 \pi\left(p t-\frac{x}{5}\right)$. Then the ratio of maximum particle velocity to wave velocity is ...........
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Equation of travelling wave

$y=a \sin 2 \pi\left(p t-\frac{x}{5}\right)$

Maximum particle velocity $\left(v_y\right)=A \omega$ or $v_y=a \times 2 \pi p$

Wave velocity $(v)=\frac{\omega}{k}=\frac{2 \pi p}{2 \pi / 5}=5 p$

$\therefore \frac{v_y}{v}=\frac{2 \pi a}{5}$

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