MCQ
The equation, $sin^2 \theta - \frac{4}{{{{\sin }^3}\,\,\theta \,\, - \,\,1}} = 1$$ -\frac{4}{{{{\sin }^3}\,\,\theta \,\, - \,\,1}}$ has :
  • A
    no root
  • B
    one root
  • C
    two roots
  • infinite roots

Answer

Correct option: D.
infinite roots
d
$sin^2 \theta = 1\, [sin\theta \ne \,\, \pm 1 ]$

$\Rightarrow \,sin\theta = 1$

$\Rightarrow \theta = 2n\pi + \pi /2$

$\Rightarrow$ infinite roots 

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