MCQ
The equation whose roots are $\frac{1}{{3 + \sqrt 2 }}$and $\frac{1}{{3 - \sqrt 2 }}$ is
- ✓$7{x^2} - 6x + 1 = 0$
- B$6{x^2} - 7x + 1 = 0$
- C${x^2} - 6x + 7 = 0$
- D${x^2} - 7x + 6 = 0$
${x^2} - \left( {\frac{1}{{3 + \sqrt 2 }} + \frac{1}{{3 - \sqrt 2 }}} \right)x + \frac{1}{{3 + \sqrt 2 }} \times \frac{1}{{3 - \sqrt 2 }} = 0$
$ \Rightarrow {x^2} - \left( {\frac{6}{7}} \right)x + \frac{1}{7} = 0 \Rightarrow 7{x^2} - 6x + 1 = 0$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.