MCQ
The equation ${x^2} + {y^2} + 4x + 6y + 13 = 0$ represents
  • A
    Circle
  • B
    Pair of coincident straight lines
  • C
    Pair of concurrent straight lines
  • Point

Answer

Correct option: D.
Point
d
(d) Point circle ( radius is zero).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Consider the quadratic equation $n x^2+7 \sqrt{n x+n}=0$ where $n$ is a positive integer. Which of the following statements are necessarily correct?

$I$. For any $n$, the roots are distinct.

$II$. There are infinitely many values of $n$ for which both roots are real.

$III$. The product of the roots is necessarily an integer.

The sum of the first $20$ terms of the series $5+11+$ $19+29+41+\ldots$ is $..........$.
The figures $4,\, 5,\, 6,\, 7, \,8 $ are written in every possible order. The number of numbers greater than $56000$ is
Let $P = \{ (x,\,y)|{x^2} + {y^2} = 1,\,x,\,y \in R\} $. Then $P$ is
If the shortest distance between the line $\frac{x-4}{1}=\frac{y+1}{2}=\frac{z}{-3}$ and $\frac{x-\lambda}{2}=\frac{y+1}{4}=\frac{z-2}{-5}$ is $\frac{6}{\sqrt{5}}$, then the sum of all possible values of $\lambda$ is :
Let the vectors $\overrightarrow{ u }_1=\hat{ i }+\hat{ j }+ a \hat{ k }, \overrightarrow{ u }_2=\hat{ i }+ b \hat{ j }+\hat{ k }$ and $\overrightarrow{ u }_3=c \hat{ i }+\hat{ j }+\hat{ k }$ be coplanar. If the vectors $\overrightarrow{ v }_1=(a+b) \hat{i}+c \hat{j}+c \hat{k}, \quad \overrightarrow{ v }_2=a \hat{i}+(b+c) \hat{j}+a \hat{k} \quad$ and $\overrightarrow{ v }_3=b \hat{ i }+ b \hat{ j }+( c + a ) \hat{ k }$ are also coplanar, then $6( a +$ $b + c )$ is equal to $..............$.
The value of $m$ for which the function $f(x) = \left\{ \begin{array}{l}m{x^2},\,x \le 1\\\,\,\,\,2x,\,x > 1\end{array} \right.$ is differentiable at $x = 1$, is
The area (in sq, units) of the quadrilateral formed by the tangents at the end points of the latera recta to the ellipse $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{5} = 1$ is :
$\log ab - \log |b| = $
The number of solutions of the equation $2 \theta-\cos ^{2} \theta+\sqrt{2}=0$ is $R$ is equal to