MCQ
The equilateral triangle $ABC$ is cut from a thin solid sheet of wood. (See figure) $D, E$ and $F$ are the mid points of its sides as shown and $G$ is the centre of the triangle. The moment of inertia of the triangle about an axis passing through $G$ and perpendicular to the plane of the triangle is $I_0.$ If the smaller triangle $DEF$ is removed from $ABC,$ the moment of inertia of the remaining figure about the same axis is $I.$ Then
- ✓$I = \frac{{15}}{{16}}{I_0}$
- B$I = \frac{{3}}{{4}}{I_0}$
- C$I = \frac{{9}}{{16}}{I_0}$
- D$I = \frac{{{I_0}}}{4}$
