MCQ
The equilibrium $2S{O_{2(g)}} + {O_{2(g)}}$ $\rightleftharpoons$ $2S{O_{3(g)}}$ shifts forward, if
- AA catalyst is used
- BAn adsorbent is used to remove $S{O_3}$ as soon as it is formed
- CLow pressure
- DSmall amounts of reactants are used
When an adsorbent removes $SO _3$ as soon as it is formed, the equilibrium will shift in the forward direction so that more and more $SO _3$ is formed which will nullify the effect of decrease in the concentration of product.
When small amounts of reactants are removed, the equilibrium will shift in the backward direction so as to nullify the effect of decrease in the reactant concentration.
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$(i)$ ${C_6}{H_5}{N^ + } \equiv NC{l^ - }$ $(ii)$ ${C_6}{H_5}{N^ + } \equiv N$
$(iii)$ ${{\overset{\centerdot }{\mathop{C}}\,}_{6}}{{H}_{5}}$ $(iv)$ $C_6H_5Cl$