Since $R$ cannot be negative, hence $R = \frac{{1 + \sqrt 5 }}{2}\,\Omega $
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
In the figure, the potentiometer wire $AB$ of length $L$ and resistance $9r$ is joined to the cell $D$ of $emf$ $\varepsilon $ and internal resistance $r$. The cell $C's$ $emf$ is $\frac{\varepsilon }{2}$and its internal resistance is $2r$. The galvanometer $G$ will show no deflection when the length $AJ$ is
In the circuit shown, the reading of the ammeter (ideal) is the same with both switches open as with both closed find the value of resistance $R$ in $ohm$ . ................ $\Omega$
Coefficient of linear expansion of material of resistor is $\alpha$. Its temperature coefficient of resistivity and resistance are $\alpha_\rho$ and $\alpha_R$ respectively, then correct relation is
Two wires $A$ and $B$ of the same material, having radii in the ratio $1: 2$ carry currents in the ratio $4: 1$. The ratio of drift speed of electrons in $A$ and $B$ is
If an electron revolves in the path of a circle of radius of $0.5 × 10^{-10}\, m$ at frequency of $5 × 10^{15}$ $cycles/s$ the electric current in the circle is ..................$mA$ (Charge of an electron $=1.6 × 10^{-19}\, C$ )
Two resistances of $400\,\Omega $ and $800\,\Omega $ are connected in series with a $6\,volt $ battery of negligible internal resistance. A voltmeter of resistance $10,000\,\Omega $ is used to measure the potential difference across $400\,\Omega $ . The error in the measurement of potential difference (in volt) approximately is