MCQ
The expression $(a-b)^3+(b-c)^3+(c-a)^3$ can be factorized as.
- ✓$3(a - b) (b - c) (c - a)$
- B$3 a^3 b^3 b c^3$
- C$[a-(b+c)]^3$
- D$3abc$
✓
Answer
Correct option: A.
$3(a - b) (b - c) (c - a)$
Here, $a - b + b - c + c - a = 0$
Therefore, $(a-b)^3+(b-c)^3+(c-a)^3$
$= 3(a - b) (b - c) (c - a)$
Therefore, $(a-b)^3+(b-c)^3+(c-a)^3$
$= 3(a - b) (b - c) (c - a)$
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