The extension in a string, obeying Hooke's law, is $x$. The speed of sound in the stretched string is $v$. If the extension in the string is increased to $1.5x$, the speed of sound will be
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$\therefore v=\sqrt{\frac{T}{\mu}},$ where $T=$ tension in string
$\mu$ is the linear mass density
$\therefore \frac{v}{v^{\prime}}=\sqrt{\frac{T}{T^{\prime}}} \Rightarrow \frac{v}{v^{\prime}}=\sqrt{\frac{x}{1.5 x}}$
$\Rightarrow v^{\prime}=v \times \sqrt{1.5}$
$\Rightarrow v^{\prime}=1.22 v$
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