The extension in a string obeying Hooke's law is $x.$ The speed of sound in the stretched string is $v.$ If the extension in the string is increased to $1.5x$, the speed of sound will be
IIT 1996, Diffcult
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(a) Speed of sound in a stretched string $v = \sqrt {\frac{T}{\mu }} $…$(i)$
Where $T$ is the tension in the string and $\mu $ is mass per unit length.
According to Hooke’s law, $F \propto x$ $T \propto x$…$(ii)$
From $(i)$ and $(ii)$ $v \propto \sqrt x $ $\Rightarrow$ $v' = \sqrt {1.5} \;v = 1.22\;v$
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A surface of area $S$ is placed perpendicular to the direction of travel of a plane wave. The energy per unit time intercepted by the surface is $E$ when the amplitude of the wave is $A$ . The area of the surface is reduced to $\frac{1}{2} \ S$ and the amplitude of the wave is increased to $2\ A$ . What is the energy per unit time intercepted by this smaller surface?
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