MCQ
The factorisation $1 + 16x + 64x^2$ is:
  • A
    $(1 - 8x)^2$
  • $(1 + 8x)^2$
  • C
    $(8 - x)^2$
  • D
    $(8 + x)^2$

Answer

Correct option: B.
$(1 + 8x)^2$
B.  $(1 + 8x)^2$
Solution:
$1 + 16x + 64x^2$
$= (1)2 + 2(1) (8x) + (8x)^2 = (1 + 8x)^2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free