MCQ
The factorisation of $12 a^{2} b+15 a b^{2}$ gives:
  • A
    $3 a b(4 a b+5)$
  • B
    $3 a b(4 a+5$
  • C
    $3 a(4 a+5(b)$
  • $3 b(4 a+5(b)$

Answer

Correct option: D.
$3 b(4 a+5(b)$
d
$12 a^{2} b+15 a b^{2}$
$12 a^{2} b=3 \times 4 \times a \times a \times b$
$15 a b^{2}=3 \times 5 \times a \times b \times b$
The common factors are $3 a b$.
$12 a^{2} b+15 a b^{2}=3 a b(4 a+5 b)$

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