MCQ
The factorisation of $(1+m)^{2}-4 \mid m$ is
- ✓$(1-m)^{2}$
- B$(1+m-2)^{2}$
- C$(1+m+2)^{2}$
- Dnone of these
✓
Answer
Correct option: A.
$(1-m)^{2}$
a
$(1+m)^{2}-4 \ln$
$=\left.\right|^{2}+m^{2}+2 \operatorname{lm}-4 \mid m$
$=\left.\right|^{2}-2 \mid m+m^{2}=(\mid-m)^{2}$
$(1+m)^{2}-4 \ln$
$=\left.\right|^{2}+m^{2}+2 \operatorname{lm}-4 \mid m$
$=\left.\right|^{2}-2 \mid m+m^{2}=(\mid-m)^{2}$
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