MCQ
The factorisation of $36 x^{2} y^{2}-1$ is
- ✓$(6 x y-1)(6 x y+1)$
- B$(6 x y-1)^{2}$
- C$(6 x y+1)^{2}$
- D$(6+x y)^{2}$
✓
Answer
Correct option: A.
$(6 x y-1)(6 x y+1)$
a
$36 x^{2} y^{2}-1=(6 x y)^{2}-(1)^{2}$
$=(6 x y-1)(6 x y+1)$
$36 x^{2} y^{2}-1=(6 x y)^{2}-(1)^{2}$
$=(6 x y-1)(6 x y+1)$
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