MCQ
The factorisation of $6 - x - 2x^2$ is:
- ✓$(2 + x) (3 - 2x)$
- B$(2 + x) (3 + 2x)$
- C$(2 - x) (3 - 2x)$
- D$(2 - x) (3 + 2x)$
✓
Answer
Correct option: A.
$(2 + x) (3 - 2x)$
A. $(2 + x) (3 - 2x)$
Solution:
$= 6 - x - 2x^2$
$= 6 + 3x - 4x - 2x^2$
$= 3(2 + x) - 2x (2 + x)$
$= (2 + x) (3 - 2x)$
Solution:
$= 6 - x - 2x^2$
$= 6 + 3x - 4x - 2x^2$
$= 3(2 + x) - 2x (2 + x)$
$= (2 + x) (3 - 2x)$
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