MCQ
The factorisation of $am^2 + bm^2 + bn^2 + an^2$ is:
  • A
    $(a + b) (m^2 - n^2)$
  • $(a + b) (m^2 + n^2)$
  • C
    $(a - b) (m^2 + n^2)$
  • D
    $(a - b) (m^2 - n^2)$

Answer

Correct option: B.
$(a + b) (m^2 + n^2)$
B.  $(a + b) (m^2 + n^2)$
Solution:
$= am^2 + bm^2 + bn^2 + an^2$
$= m^2(a + b) + n^2(b + a)$
$= (a + b) (m^2 + n^2)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free