The factorisation of (l + m)^2 - 4lm is: - Vidyadip

MCQ

The factorisation of $(l + m)^2 - 4lm$ is:

✓
$(l – m)^2$
B
$(l + m - 2)^2$
C
$(l + m + 2)^2$
D
None of these.

✓

Answer

Correct option: A.

$(l – m)^2$

A. $(l - m)^2$
Solution:
$= (1 + m)^2 - 4lm$
$= l^2 + m^2 + 2lm - 4lm$
$= l^2 - 2lm + m^2 = (l - m)^2$

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